(x+2)^2+2(x+2)-8=0

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Solution for (x+2)^2+2(x+2)-8=0 equation: 



(x+2)^2+2(x+2)-8=0

We multiply parentheses

(x+2)^2+2x+4-8=0

We add all the numbers together, and all the variables

2x+(x+2)^2-4=0

We move all terms containing x to the left, all other terms to the right

2x+(x+2)^2=4

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